There corresponds to each physical quantity of a quantum mechanical system, a unique hypermaximal Hermitian operator, as we know..., and it is convenient to assume that this correspondence is one-to-one -- that is, that actually each hypermaximal operator corresponds to a physical quantity. (von Neumann 1932 [1955], p.313)The problem is that von Neumann's "convenient assumption," that self-adjoint operators correspond to observable quantities, can't possibly be true. Here's a (probably too)* simple example to illustrate. Suppose we have a 2-dimensional Hilbert space (it might be describe the z-spin of a single particle), generated by the states ψ0 and ψ1. And let A be a self-adjoint operator for which these are eigenstates:
Construct two new states, φ0 and φ1, given by:
Now let B be a self-adjoint operator for which these new states are eigenstates, say,
The problem is that, although both A and B are self-adjoint, they can't both at the same time represent observable quantities. For suppose the eigenstates of A correspond to observable measurements; then the eigenstates of B are not observable states, since they are linear superpositions of the eigenstates of A. But it's not possible to observe superpositions of physics measurements. And the same holds conversely if the eigenstates of B correspond to observable measurements. So, which one is the real observable? It seems we're in a pickle.
One simple way to resolve the pickle is to impose a rule, which says constructed operators like B are not allowed to be observables. That's a superselection rule.
A typical way to implement such a rule is to notice that we can think of our Hilbert space as a direct sum of one-dimensional Hilbert spaces H0 and H1, one containing ψ0 and the other containing ψ1:
We can motivate this decomposition as long as we agree that both ψ0 and ψ1 correspond to readings of a measurement device. We can then impose a superselection rule:
Linear superpositions of states from distinct sectors in such a direct sum are not physically realizable except as a mixture, and hence cannot be eigenstates.Wightman attributes this particular rule to Wigner, in his excellent history of superselection rules. John Earman has recently written on some of the philosophical details. Of course, it may not be true that "we agree" on what states correspond to readings of measurement devices. And in such cases, the question of which superselection rules are justified remains a difficult problem in the foundations of physics.
* Added.




9 comments:
Wait, are you arguing here that the spin along the x-axis is not a physical observable? Or are you arguing that there is a privileged basis in QM in which we must consider operators, and that the other bases are somehow deficient? That would certainly sound like it's problematic for Lorentz symmetry...
It's certainly true that since Lx and Lz don't commute it's not possible to measure both simultaneously, but they are both operators with observable eigenstates. You can even measure them sequentially (though this is most often done with photon polarizations) and observe how it's possible to measure both and how the measurement process alters the state of the measured photon.
I haven't looked closely at superselection rules, myself, but the way you present them here makes them sound like bunk to me.
What's more, to claim that it is not possible to measure the eigenstates of all possible Hermitian operators seems to be getting a little ahead of yourself. The measurement process isn't even well defined quantum mechanically, yet, so I don't see how you can make such a categorical statement without effectively adding it to the definition of what a measurement is.
Ooops, I just reread the article. You're not necessarily talking about spin... My bad.
Still not a fan of superselection or supersymmetry, for that matter.
Blackgriffin: You're right, this example may just be too simple-minded. Obviously, both A and B can be observables in this situation (as in the example of spin, as you mention), they just don't commute. I was just trying to come up with some dirt-simple situation in which someone might try to rule out entanglements between states in distinct sectors. This example obviously isn't a *plausible* rule, so I suppose I should keep looking...
Superselection and supersymmetry are closely tied together (on some accounts, you have one iff you have the other). So at least you're consistent. :)
If you want to be concrete about it, just use the eigenstates of the charge operator. While we have observed superpositions of particle and anti-particle (K' mesons, the K_long and K_short are superpositions), we have not observed superpositions of, say, electron and anti-electron, or K+ and K- for that matter.
BG
Hm, maybe not so much. It can probably be argued that the vacuum state is a superposition of particle/anti-particle pairs (see the Dirac sea).
Tough call.
BG
Thinking about this more, perhaps this would work? Consider again the x and y spin observables Sx and Sy, on a 2-dimensional Hilbert space with basis set {ψ,φ}. Since [Sx, Sy] = i, we normally say you can't measure spin in both directions at the same time. But now construct a new *4-dimensional* Hilbert space, using the basis set {(ψ,ψ),(ψ,φ),(φ,ψ),(φ,φ)}, with each basis-element representing the measurement of x-spin and y-spin at the same time. Then the self-adjoint operator A having these four basis-elements as eigenstates would be an "observable," which measures both x-spin and y-spin at the same time!
Presumably, A isn't really an observable (it seems it can't be, if our interpretation of [Sx, Sy]=i is correct). So maybe here a superselection rule is appropriate. The 4D Hilbert space is a direct sum of two copies of the 2D Hilbert space. And the eigenstates of A superpositions of pure states from distinct sectors. But this isn't allowed according to Wigner's rule. So, A isn't an admissible observable, because its "eigenstates" aren't admissible pure states.
Sorry, that should read "the eigenstates of A are superpositions.
I don't know whether that works or not. It would seem to depend on whether it makes sense to take a direct product (or sum, I have a hard time keeping them straight) of different bases in the same space. If it does, then great, I think you've got a winner there, though I think it sounds a little more detailed than what you'd want for a lay audience. If you're shooting for "someone who remembers their undergrad quantum reasonably well," it should be Ok.
BG
Good. I'll give it a more careful work-through when I've got a moment. Many thanks for the helpful comments!